Exercise 2
This question can stand alone as an exercise that examines the criteria that need to be met before using a parametric ANOVA. However, the ideas examined here are extended in interactive exercise 2 in Chapter 8.
Example W7.2: The inhibitory effect of oregano oil and selected antibiotics on certain bacteria
As part of a larger investigation an undergraduate examined the effectiveness of the essential oil from oregano in comparison with a number of antibiotics including streptomycin. Each potential bactericide was added to a small disc of paper and placed onto agar plates that had been inoculated either with Escherichia coli or Pseudomonas aeruginosa. After incubating the plates for 24 hours at 370c the zone of inhibition was recorded. The zone of inhibition is the mean diameter of the area of clear agar around the discs containing the substance under test (Table W7.5). The size of the zone of inhibition indicates the area over which the bacteria have been killed or their growth inhibited. Eight replicate plates were used for each treatment.
Table W7.5: The mean diameter of the zone of inhibition (mm) produced on agar plates inoculated either with Escherichia coli or Pseudomonas aeruginosa as a result of treatment with either oregano essential oil or streptomycin
Mean diameter of zone |
of inhibition (mm) |
|
|---|---|---|
E. coli |
P. aeruginosa |
|
Streptomycin |
17.0 |
12.0 |
16.0 |
11.0 |
|
16.0 |
11.0 |
|
15.0 |
10.0 |
|
16.0 |
10.0 |
|
16.0 |
11.0 |
|
16.0 |
11.0 |
|
17.0 |
11.0 |
|
Oregano oil |
21.0 |
10.0 |
22.0 |
9.0 |
|
21.0 |
10.0 |
|
21.0 |
10.0 |
|
24.0 |
10.0 |
|
22.0 |
10.0 |
|
20.0 |
10.0 |
|
22.0 |
10.0 |
1 |
2 |
The full calculation for Q W2.2 is as follows:
There are seven criteria in section 7.7.1. Two of these criteria are/may not be met.
Criteria |
Met? |
|---|---|
1. Wish to test for differences in population means |
Yes. |
|
2. Have two treatment variables. |
Yes (species of bacteria and potential bactericide). |
|
3. Have parametric data. |
Possibly. We can assume this but know that this assumption is only based on the fact that the data are measured on an interval scale of measurement. |
|
4. Allocate all items at random to each sample. |
Yes. Each agar plate was allocated at random to either the streptomycin treatment or the oregano treatment. |
|
5. Have variances that are similar (homogeneous). |
This criterion is checked using an Fmax test (BOX 7.5). In this example it is clear that the variances are not homogeneous. The variances for the four samples are included in the calculation table (W7.6). Fmax calculated = 1.41071 / 0.125 = 11.28571 a (number of samples) = 4 At p = 0.05, Fmax critical = 8.44. Therefore Fmax calculated (11.29) is greater than Fmax critical (8.44) and the variances are not homogeneous. (We show you how to calculate Fmax using statistical software in the 'full calculations - statistical software BOX 7.5 on these web pages). |
|
6. Have the same number of replicates (observations) in each sample. |
Yes. There are 8 plates for each treatment. |
|
7. Have an orthogonal design |
Yes. Both species of bacteria were tested with each of the potential bactericide treatments. |
Table W7.6: Calculation of summary statistics for the mean diameter of the zone of inhibition (mm) produced on agar plates inoculated either with Escherichia coli or Pseudomonas aeruginosa as a result of treatment with either oregano essential oil or streptomycin
Mean diameter of zone |
of inhibition (mm) |
|
|---|---|---|
E. coli |
P. aeruginosa |
|
Streptomycin |
17 |
12 |
16 |
11 |
|
16 |
11 |
|
15 |
10 |
|
16 |
10 |
|
16 |
11 |
|
16 |
11 |
|
17 |
11 |
|
16.125 |
10.875 |
|
2083 |
949 |
|
129 |
87 |
|
s2 |
0.410714285 |
0.410714285 |
n |
8 |
8 |
Oil |
21 |
10 |
22 |
9 |
|
21 |
10 |
|
21 |
10 |
|
24 |
10 |
|
22 |
10 |
|
20 |
10 |
|
22 |
10 |
|
21.625 |
9.875 |
|
3751 |
781 |
|
173 |
79 |
|
s2 |
1.410714286 |
0.125 |
n |
8 |
8 |